7(10y^2-5)=y

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Solution for 7(10y^2-5)=y equation:


Simplifying
7(10y2 + -5) = y

Reorder the terms:
7(-5 + 10y2) = y
(-5 * 7 + 10y2 * 7) = y
(-35 + 70y2) = y

Solving
-35 + 70y2 = y

Solving for variable 'y'.

Reorder the terms:
-35 + -1y + 70y2 = y + -1y

Combine like terms: y + -1y = 0
-35 + -1y + 70y2 = 0

Factor a trinomial.
(-7 + -10y)(5 + -7y) = 0

Subproblem 1

Set the factor '(-7 + -10y)' equal to zero and attempt to solve: Simplifying -7 + -10y = 0 Solving -7 + -10y = 0 Move all terms containing y to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -10y = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -10y = 0 + 7 -10y = 0 + 7 Combine like terms: 0 + 7 = 7 -10y = 7 Divide each side by '-10'. y = -0.7 Simplifying y = -0.7

Subproblem 2

Set the factor '(5 + -7y)' equal to zero and attempt to solve: Simplifying 5 + -7y = 0 Solving 5 + -7y = 0 Move all terms containing y to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -7y = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -7y = 0 + -5 -7y = 0 + -5 Combine like terms: 0 + -5 = -5 -7y = -5 Divide each side by '-7'. y = 0.7142857143 Simplifying y = 0.7142857143

Solution

y = {-0.7, 0.7142857143}

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